Consider the following equilibrium: b(aq)+h2o(l)⇌hb+(aq)+oh−(aq) suppose that b(aq) is added to a solution of b at equilibrium. you may want to reference (pages 718 - 720) section 17.1 while completing this problem. part a will the equilibrium constant for the reaction increase, decrease, or stay the same? will the equilibrium constant for the reaction increase, decrease, or stay the same? the equilibrium constant for the reaction will stay the same. the equilibrium constant for the reaction will decrease. the equilibrium constant for the reaction will increase. submitrequest answer part b will the concentration of hb+(aq) increase, decrease, or stay the same? will the concentration of increase, decrease, or stay the same? the concentration of hb+(aq) will stay the same. the concentration of hb+(aq) will increase. the concentration of hb+(aq) will decrease.

A. The equilibrium constant for the reaction will stay the same.

B. The concentration of HB⁺(aq) will increase.

Explanation:

For the equilibrium:

B(aq) + H₂O(l) ⇌ HB(aq) + OH⁻(aq)

The equilibrium constant is:

K = [HB] [OH⁻] / [B]

A. The increase of B concentration will produce HB and OH⁻ in order to maintain the equilibrium constant for the reaction constant.

B. By LeChatelier's principle. An increase in the concentration of a reactant will result in predictable and opposing changes in the system that are the production of more HB(aq) and OH⁻(aq). Thus, the concentration of HB⁺(aq) will increase.

I hope it helps!

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72

5.6⋅10−^19  j

do you need the explaination?