Experimental procedure
note: to save time you should start the ion exchange process and as it proceeds perform your
- other titrations. place a 10 ml aliquot of your sample into the column, and immediately begin
collecting the effluent into a titration flask. once the aliquot of sample has reached the top of the
ion exchange resin, add 25 ml of distilled water and collect the effluent until the distilled water
is at the top of the ion exchange resin. you will use at least three aliquots each one individually
titrated
without passing aliquots through the ion exchange column: titrate three 10 ml aliquots
using standardized naoh and using phenolphthalein indicator. h+
after passing aliquots through the ion exchange column: titrate three 10 ml aliquots
using standardized naoh and using phenolphthalein indicator. maematiitti coll
without passing aliquots through the ion exchange column: titrate three 10 ml aliquots
3- after addition of enough naoh to neutralize the acid, 50 ml of ammonia buffer and three
drops of calmagite indicator and titrate with standàrdized edta.
maf
calculate the molar concentration of each ion present in the original sample.

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answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.