Identify which sets of quantum numbers are valid for an electron. note that each set is ordered (n, l,ml, ms).
group of answer choice.
a) 2, -1. 1, -1/2
b) 2, 1, 0 , 1/2
c) 3, 2, 1, -1
d) 4, 3, 2, 1/2
e) 4, 3, -4, 1/2
f) 1, 1, 0, 1/2
g) 1, 1, 0, -1/2
h) 3, 0, 0, 1/2
i) 0, 2, 0, 1/2
j) 3, 2, 2, 1/2
k) 1, 2, 0, -1/2

The answer to your question is:

Explanation:

Quantum numbers have the numbers

n = from 1 to 7

l = s = 0 p = 1 d = 2  f= 3

m = ± l

s = ±1/2

Group of answer choice.

A) 2, -1. 1, -1/2     The option is incorrect "l" could not be negative

B) 2, 1, 0 , 1/2       The option is posible

C) 3, 2, 1, -1          This option is incorrect "s" can not value -1

D) 4, 3, 2, 1/2       This option is correct

E) 4, 3, -4, 1/2      This option is incorrect "m2 can not value -4

F) 1, 1, 0, 1/2         This option is incorrect, the second number is not posible

G) 1, 1, 0, -1/2        This option is incorrect the second number could not be 1.

H) 3, 0, 0, 1/2       This option is incorrect "l" can not value 0

I) 0, 2, 0, 1/2         This option is incorrect, n can not value 0

J) 3, 2, 2, 1/2        This option is correct

K) 1, 2, 0, -1/2       This option is incorrect "l" can not value 2.

the ratio of the conjugate base to the acid required to attain the desired ph.