What is the theoretical mass of xenon tetrafluoride that should form when 130.g of xenon is reacted with 100.g of f2? what is the percent yield if only 145g of xef4 is actually isolated?

The answer to your question is: 70.7 %

Explanation:

Equation

                  Xe   +   2F₂    ⇒    XeF₄

limiting reactant = Xe

Xe is the limiting reactant because the ratio is:

theoretical = 131/ 76 = 1.72 g

experimental ratio = 130/100 = 1.3  the amount of F increased.

                     131.3 g of Xe 207 g of XeF₄

                     130 g of Xe    x

                         x = (130 x 207) / 131.3

                        x = 205 g of XeF₄

% yield = 145 / 205 x 100

% yield = 70.7

the temperature of the gas, in k, not celsius.