How many joules of heat energy are released when 50.0g of water are cooled from 70.0c to 60.0c

2090 Joules

Explanation:

Heat energy is calculated by multiplying the mass of a substance by its specific heat capacity and by change in temperature.

That is;

Quantity of heat = Mass × specific heat capacity × change in temperature

Q = m×c × ΔT

In this case; we need to calculate the heat energy released by water

Mass of water = 50.0 g

Specific heat capacity of water = 4.18 J/g°C

Change in temperature = 10 °C ( 70°C - 60°C)

therefore;

Heat released = 50 g × 4.18 J/g°C × 10 °C

                       = 2090 Joules

Thus, the heat energy released when 50 g of water is cooled from 70°C to 60°C is 2090 Joules

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