Howard describes a model system used to test the molecular weight distribution of acondensation polymer (g. j. howard, j. polym. sci. 37, 310 (1959)): "the polymer sample was an acetic acid-stabilized equilibrium nylon-6,6. analysis showed it to have the following end group composition (in equivalents per 106 g): acetyl = 28.9, amine = 35.3 and carboxyl = 96.5. the number average degree of polymerization is, therefore, 110 and the conversion degree (= extent of reaction) = 0.9909.for nylon-6,6, 99% of the carboxylic acid groups are know to have reacted.
calculate the average of mn, mw and mz.

Answer the same molecular formula;

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Use the universal gas law formula: pv = nrt now, the key word in this problem is stp, so at stp, temperature will always be 0 degrees celsius and pressure will always be 1.0 atm or 760 torr. given something is at stp, we already know the two variables pressure and temperature. the other thing we can find with the given information is moles. to find moles, just divide grams by molar mass of the element. 16.0g / 2(16.00)g/mol = 0.5 moles plug the values in to the equation pv = nrt (1.0 atm)( x ) = (0.5 )(0+273=273k) the r value is just a constant for when we use atm, liters, moles and kelvin. i'm assuming you want your answer in liters, but if you dont just move the decimal 3 to the right in your final answer. so when plugging these numbers in to your calculator and trying to find x, you get 11.20665 liters using significant figures the answer is 11.2 liters