Awetted-wall absorption tower is fed with water as the wall liquid and an ammonia-air gas mixture as the central-core gas. at a particular level in the tower, the ammonia concentration in the bulk gas is 80 mol%, that in the bulk liquid 5 mol%. the temperature is 30 c and the pressure 1 atm. the local mass transfer in the liquid is kl = 2.87*10-5 m/s and in the gas is kc = 0.0362 m/s. calculate the local molar flux for the absorption of ammonia using the overall mass-transfer coefficient ky, ignoring the vaporization of water.

note: for this problem, use equilibrium data of nh3-water from appendix a.3-22 from the textbook.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied