Asolution of hno, is standardized by reaction with pure sodium carbonate 2h*+na, co,2 nat +h0+co a volume of 24.76 t 0.05 ml of hno, solution was required for complete reaction with 0.9452 + 0.0007 g of na, co, (fm 105.988 0.001 g/mol). find the molarity of the hno, solution and its absolute uncertainty. note: significant figures are graded for this problem. to avoid rounding errors, do not round your answers until the very end of your calculations m t 0.002 m hno,]= 0.7372

Challenge question: this question is worth 6 points. as you saw in problem 9 we can have species bound to a central metal ion. these species are called ligands. in the past we have assumed all the d orbitals in some species are degenerate; however, they often are not. sometimes the ligands bound to a central metal cation can split the d orbitals. that is, some of the d orbitals will be at a lower energy state than others. ligands that have the ability to cause this splitting are called strong field ligands, cnâ’ is an example of these. if this splitting in the d orbitals is great enough electrons will fill low lying orbitals, pairing with other electrons in a given orbital, before filling higher energy orbitals. in question 7 we had fe2+, furthermore we found that there were a certain number (non-zero) of unpaired electrons. consider now fe(cn)6 4â’: here we also have fe2+, but in this case all the electrons are paired, yielding a diamagnetic species. how can you explain this?