Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide: in a particular experiment, a 2.00 g sample of a cao is reacted with excess water and 2.14 grams of ca(oh)2 is recovered. what is the percentage yield of this experiment?

The answer to your question is:  yield = 81 %

Explanation:

Data

Calcium oxide mass = 2 g

Calcium hydroxide mass = 2.14 g

yield = ?

Process

Reaction

                     CaO   +   H₂O    ⇒     Ca(OH)₂

MW CaO = 40 + 16 = 56 g

MW Ca(OH)₂ = 40 + 32 + 2 = 74 g

                  56 g of CaO   74 g of Ca(OH)₂

                  2 g                    x

                 x = (2 x 74)/ 56

                 x = 2.64 g of  Ca(OH)₂

yield = experimental / theoretical x 100

yield = 2.14 / 2.64 x 100

yield = 81 %

you gotta add the following molecules so we can give u an answer

explanation: