consider the following balanced reaction : 2naoh +co2> na2co3 +h2o.

3 moles of naoh and 4 moles of co2 are allowed to react according to the above equation .

(i)which reagent is the limiting reagent?

(ii) what is the maximum number of moles of na2co3 that can be formed

(iii) how many moles of excess reagant remain unreacted? (iv) if the actual mass na2co3 produced was 0.5 mol, what percentage yield of na2co3?

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of carbon is as shown here in the image.

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.