When a peptide bond is formed between two amino acids, one is attached to the trna occupying the p site and the other view available hint(s) when a peptide bond is formed between two amino acids, one is attached to the trna occupying the p site and the other is attached to the trna occupying the a site is attached through hydrogen bonds to the mrna is moved to the e site is free in the cytoplasm is attached to the trna occupying the e site submit part c which of the following statements concerning peptide bond formation is correct? view available hint(s) which of the following statements concerning peptide bond formation is correct? it is catalyzed by an enzymatic protein. it uses water. it is catalyzed by peptidyl transferase. it is energetically favorable and occurs spontaneously at the a and p sites. it requires gtp. submit return to assignment provide feedback completed. no additional followup.

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years