At 900.0 k, the equilibrium constant (kp) for the following reaction is 0.345. 2so2 + o2(g) → 2so3(g) at equilibrium, the partial pressure of so2 is 35.0 atm and that of o2 is 15.9 atm. the partial pressure of so3 is atm. at 900.0 k, the equilibrium constant (kp) for the following reaction is 0.345. 2so2 + o2(g) → 2so3(g) at equilibrium, the partial pressure of so2 is 35.0 atm and that of o2 is 15.9 atm. the partial pressure of so3 is atm. 192 6.20 × 10-4 4.21 × 10-3 40.2 82.0

The partial pressure of SO₃ is 82.0 atm

Explanation:

The equilibrium constant Kp is equal to the equilibrium pressure of the gaseous products raised to the power of their stoichiometric coefficients divided by the equilibrium pressure of the gaseous reactants raised to the power of their stoichiometric coefficients.

For the reaction,

2 SO₂(g) + O₂(g) → 2 SO₃(g)

plasma is the state of matter where the substance is ionized and has no definite shape or volume. the fact of being ionized makes the substance a good electrical conductor.

answer: cellular respiration takes in food and uses it to create atp, a chemical which the cell uses for energy. usually, this process uses oxygen, and is called aerobic respiration. it has four stages known as glycolysis, link reaction, the krebs cycle, and the electron transport chain.