When the following equation is balanced the coefficient of oxygen is
__c3h4 + __o2 → __co2 + _h20
a. 1
b. 2
c. 3
d. 4

When the equation is balanced, the coefficient of oxygen is 4. The correct option is d. 4

The given equation is __C3H4 + __O2 → __CO2 + _H20

This is the equation of the reaction between Propyne (C₃H₄) and Oxygen(O₂) to give Carbon(IV)oxide(CO₂) and Water (H₂O).  

To determine the coefficient of oxygen when the equation is balanced,

First, we will write the balanced form of the equation.

C₃H₄ + O₂ → CO₂ + H₂O

To balance the equation, we will ensure that the same number of each element is represented on the reactant and product sides ( that is, obey the law of conservation of matter)

The balanced form of the equation is

C₃H₄ + 4O₂ → 3CO₂ + 2H₂O

C = 3

H = 4

O = 8

C = 3

H = 4

O = 8

Therefore, the equation is balanced

From the balanced equation, we can observe that the coefficient of oxygen is 4.

Hence, when the equation is balanced, the coefficient of oxygen is 4. The correct option is d. 4

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The answer to your question is:  4

Explanation:

                      __C3H4   +    _4O2    →     _3CO2    +    2H20

                                          3      C   3

                                          4     H   4

                                         8       O   8

they are both synthetic elements

explanation:

d

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.