Correct first answer= brianliest! would really appreciate if you’d me out: ’(

The answer to your question is: 2 grams of methane

Explanation:

Data

V = 9.15 l

P = 1.77 atm

T = 57° C = 330 °K

Ar mass = 19 g

CH4 mass = ?

Formula

PV = nRT

Process

                             n = 0.6

Argon

                     40 g of Ar -------------------- 1 mol

                      19 g         ---------------------   x

                                 x = 0.475 mol of Ar

moles of CH4 = 0.6 - 0.475

                       = 0.125

Methane

                            16 g of CH4 ---------------  1mol

                             x                 ----------------  0.125 mol

                            x = 2 grams

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3