At a certain temperature, 0.760 mol so3 is placed in a 2.50 l container. 2so3(g)↽−−⇀2so2(g)+o2(g) at equilibrium, 0.110 mol o2 is present. calculate kc.

Explanation:

Volume of container = 2.50 L

Initial number of moles of = 0.760 mol

Initial concentration of =

                                                 = 0.304 M

No. of moles of present at equilibrium = 0.110 mol

Volume of container, V = 2.50 L

Equilibrium concentration of =

                                                     = 0.044 M

Initial:               0.304              0            0

Change:           -2x                 2x           x

Equilibrium:    0.304 - 2x        2x          x

Since, equilibrium concentration of = x

                                                                = 0.044 M

Equilibrium concentration of = 2x

                                                           =

                                                           = 0.088 M

Equilibrium concentration of = (0.304 - 2x)

                                                      = (0.304 - 2 \times 0.044)

                                                      = 0.216 M

Hence, calculate equilibrium constant () as follows.

                                  =

                                  =

Thus, we can conclude that equilibrium constant of the reaction is .

b.final

there is none because earth is stationary and flat.