You have an-empty 42-gatbarrel-and-a 10-lb bag of dry alum, al2(so4). (a) calculate the number of gallons of 0.05 m solution you can make with this amount of alumthe-materials you hve on hand. (b) suppose you put all the alum into a 42-gal-the barrel and filled it full calculate the molar concentration of the resulting solution

a) 70.074 of gallons of 0.05 M solution we can make.

b) 0.0834 M is the molar concentration of the resulting solution.

Explanation:

Concentration of alum solution = c

Moles of alum  in solution = n

Volume of solution = V

a) Mass of alum = 10 lbs = 4535.92 g

(1 lb = 453.592 g )

Molar mass of alum

Moles of alum =

Volume of alum solution of 0.05 m = V

(1 L = 0.264172 gallons)

70.074 of gallons of 0.05 M solution we can make.

b) Moles of alum =

Volume of the barrel = 42 gallons  = 158.99 L

Concentration of alum : C

0.0834 M is the molar concentration of the resulting solution.