If the aluminum block is initially at 25 ∘c, what is the final temperature of the block after the evaporation of the alcohol? assume that the heat required for the vaporization of the alcohol comes only from the aluminum block and that the alcohol vaporizes at 25 ∘c. the heat of vaporization of the alcohol at 25 ∘c is 45.4 kj/mol, the specific heat of aluminum is 0.903 j/g⋅∘c.

It is impposible to know

Explanation:

If you consider next equation, Q=mCpdT, where Q= heat flow, m= mass of aluminium block, Cp= specific heat of aluminium and dT is the difference between T2 (?) and T1 (25°C) you need more information to respond this question, as the ammount of alcohol vaporized and the mass of the aluminium block.

It is impossible to know what is the final temperature of the aluminium block because you don´t know what is its mass. Greater the mass, lower the temparature variation is. In the other hand, greater the mass of alcohol, greater the head flow, so greater the the change in temperature.

the formula would be mgso4

mgso[subscript]4

in theory, limestone is composed principally of the compound calcium carbonate - caco3, but in reality this compound is deposited in conditions involving a number of other compounds as impurities so it ends up being a mixture of many compounds.

hope this : -)

tony (lordcaos066)