Chemistry, 08.10.2019 16:20 WendigoMeow

Zinc sulfide reacts with oxygen according to the reaction 2zns(s)+3o2(g)→2zno(s)+2so2(g) a reaction mixture initially contains 5.0 molzns and 9.8 molo2. once the reaction has occurred as completely as possible, what amount (in moles) of the excess reactant remains? express your answer using two significant figures.

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Answer from: Makiyahlfton2129

The answer to your question is: Excess oxygen = 2.3 mol

Explanation:

Data

ZnS = 5 mol

O2 = 9.8 mol

Excess reactant = ?

Balanced reaction

2ZnS(s) + 3O2(g) → 2ZnO(s) + 2SO2(g)

MW ZnS = 65 + 32 = 97 x 2 = 194 g

MW O2 = 16 x 6 = 96 g

2 mol of ZnS 3 mol O2

Ratio from the reaction = 3 mol O2/ 2 mol ZnS

= 1.5

Ratio from the quantities in the experiment = 9.8 mol O2 / 5 mol of ZnS

= 1.96

Excess reactant = Oxygen because the ratio increases

2 mol of ZnS 3 mol O2

5 mol of ZnS x

x = (5 x 3) / 2

x = 7.5 mol of O2

Excess Oxygen = 9.8 mol - 7.5 mol

Excess oxygen = 2.3 mol

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For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

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