Ablock of aluminum weighing 140 g is cooled from 98.4°c to 62.2°c with the release of 1080 joules of heat. from this data, calculate the specific heat of aluminum.

Specific heat of a substance is the value that describe how the added heat energy of substance has the impact on its temperature.

Unit is

C = Q/m. ∆T

C – Specific heat

Q- heat energy (J)

M – Mass (Kg)

∆T- change in temperature (K)

Explanation:

Given data:

M= 140 g = 0.14 Kg

Q – 1080 Joules.

∆T – 98.4 – 62.2 = 36.2

Substituting  the given data in Equation

Specific heat of Aluminium  =

Explanation:

Specific heat is defined as the amount of energy required to heat or cool 1 kg of a substance by 1°C.

It is given:

energy is 1080 joules,

mass is 140g; i.e. 0.14kg,

temperature change is 98.4 - 62.2 = 36.2°C

So the specific heat of aluminum = 1080 / 0.14 / 36.2

= 213.1 J/kg/°C

hurricanes form when warm, moist air from the ocean surface quickly rises into the atmosphere and forms storm clouds and rain. when the clouds are formed, heat is released which warms the cool air in the upper regions of the atmosphere so that the cycle can continue. which two phases of the water cycle are repeated in this process?