How many grams of cu are required to replace 45.0 grams of silver nitrate?
1cu + 2agno3 -> 1cu (no3)2 +2ag

Molar mass Cu = 63.546 g/mol  and AgNO₃ = 169.87

1 Cu + 2 AgNO₃ -> 1 Cu (NO₃)₂ +2 Ag

63,546 2 * 169.87
? g Cu 45.0 

Mass ( Cu ) = 45.0 * 63,546 / 2 * 169.87

Mass ( Cu ) = 2859,57 / 339,74

Mass = 8.4169 g of Cu

hope this helps!

Theoretical temperature at which molecules stop moving and no more heat can be removed from the object. kelvin: absolute zero degrees. none of the above.