Consider the decomposition equilibrium for dinitrogen pentoxide: at a certain temperature and a total pressure of 1.00 atm, the n2o5 is 0.50% decomposed (by moles) at equilibrium.
(a). if the volume is increased by a factor of 10.0, will the mole percent of n2o5 decomposed at equilibrium be greater than, less than, or equal to 0.50%. explain.
(b) calculate the mole percent of n2o5 that will be decomposed at equilibrium if the volume is increased by a factor of 10.02n2o5(g) > 4no2 (g) + o2 (g)

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.

i don,t know so just answer mine

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.

answer: cellular respiration takes in food and uses it to create atp, a chemical which the cell uses for energy. usually, this process uses oxygen, and is called aerobic respiration. it has four stages known as glycolysis, link reaction, the krebs cycle, and the electron transport chain.