How many moles of air are there in a 3 l container at 1 atm pressure and 293
k? use pv = nrt.

Moles of air 0.1245 mol.

Explanation:

Given data:

Pressure = 1 atm

Temperature = 293 K

Volume = 3 L

Number of moles = ?

Solution:

PV = nRT

R = general gas constant = 0.0821 dm³ atm . K⁻¹ . mol⁻¹

Now we will put the values in equation

PV = nRT

n = PV / RT

n = 1 atm . 3 L /  0.0821 dm³ atm . K⁻¹ . mol⁻¹ . 293 K

n = 3 / 24.1 dm³ atm. mol⁻¹

n = 0.1245 mol

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.

plasma - state of matter made up of electrically charged particles