1a. give the formula of each product when calcium carbonate (caco3) is heated
and

b. the relative formula mass (mr) of a group 2 metal carbonate is 197
relative atomic mass (ar): c=12 o=16
calculate the relative atomic mass (ar) of the group 2 metal in the metal carbonate.
name the group 2 metal.

a) CaO and CO2 are the products formed

b) The group 2 metal is Barium

Explanation:

1A When Calcium carbonate (CaCO3) is heated (this means when there is added O2). When it's strongly heated, calcium carbonate will undergo a thermal decomposition to form calcium oxide (CaO) and carbon dioxide (CO2).

2 CaCO3 + O2 → 2CaO + 3CO2

CaO and CO2 are the products formed

B) A metal carbonate has a Molecular mass of 197 g/mole

The metal carbonate has a structural formula of Mn(CO3)x

The metal is a group 2 metal, this means it has 2 valence electrons. The oxidation number is 2

Carbonate (CO3) has an oxidation number of -2

This means the ratio metal/carbonate = 1:1

The molecular mass of carbonate = 1*12 + 3*16 = 60 g/mole

The molecular mass of the metal = 197 - 60 = 137 g/mole

The metal with molecular mass 137 g/mole is Barium.

Barium is a group 2 metal.

The metalcarbonate is BaCO3

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."