Magnesium occurs in seawater to the extent of 1.4 g magnesium per kilogram of seawater. what volume of seawater, in cubic meters, would have to be processed to produce 1.00 x 105 tons of magnesium (1 ton = 2000 lb)? assume a density of 1.025 g/ml for seawater.

Explanation:

Required amount of magnesium =

Given : 1 ton = 2000 lb

1 lb = 453.592 g

Given : 1.4 g of magnesium is produced by 1000 g of sea water

of magnesium is produced by = g of sea water

Density of sea water  = 1.025 g/ml

Volume of sea water =

1 ml =

Volume of seawater, in cubic meters is