Astandard 1.00 kg mass is to be cut from a bar of steel having an equilateral triangular cross section with sides equal to 2.50 in. the density of the steel is 7.70 g/cm3. how many inches long must the section of bar be?

The section of the bar is 2.92 inches.

Explanation:

Mass of the steel cut ,m = 1.00 kg = 1000 g

Volume of the steel bar = V = Area × height

Height of the of the  section of bar = h

Area of  Equilateral triangular =

a = 2.50 inches

Cross sectional area of the steel mass = A

Density of the steel = d =

h = 2.92 inches

The section of the bar is 2.92 inches.

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