If 500 μl of 1-octene (mw 112.22 g/mol; density 0.72 g/ml) is reacted with an excess of borane-thf followed by a reaction with naoh and hooh and 0.387 g of octanol (mw 130.23 g/mol) is isolated, what is the percent yield? (exp. 3)92.6%

3

explanation:

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explanation:

0.07 g/cm³

1.37 g/cm³

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied