Suppose you have been given the task of distilling a mixture of hexane + toluene. pure hexane has a refractive index of 1.375 and pure toluene has a refactive index of 1.497. you collect a distillate sample which has a refractive index of 1.456. assuming that the refractive index of the hexane + toluene mixture varies linearly with mole fraction, what is the mole fraction of hexane in your sample?

Explanation:

The given data is as follows.

         Refractive index of mixture = 1.456

        Refractive index of hexane = 1.375

        Refractive index of toulene = 1.497

Let mole fraction of hexane =

and, mole fraction of toulene =

Also,        

or,            

Hence, calculate the mole fraction of hexane as follows.

        refractive index mixture= mole fraction hexane × ref index hexane + mole fraction toluene × ref index toluene.

              1.456 =

               1.456 =

               0.081 =

                    =

                                = 0.66

Since,    

                          = 1 - 0.66

                          = 0.34

Thus, we can conclude that mole fraction of hexane in your sample is 0.34.        

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.