Chemistry, 01.10.2019 22:20 savannahckatz
Apure gold ring (c = 0.128 j/g°c) and pure silver ring (c = 0.235 j/g°c) have a total mass of 16.891 g . the two rings are heated to 66.887 oc and dropped into a 13.9 ml of water at 21.9 oc. when equilibrium is reached, the temperature of the water is 24.2 oc. what is the mass of gold ring? (assume a density of 0.998 g/ml for water.)
Answers: 3
+ mass of gold ring 
![[M_{G} \times 0.128 J/g^{o}C \times (66.887 - 24.2)^{o}C] + [M_{s} \times 0.235 J/g^{o}C \times (66.887 - 24.2)^{o}C]](/tpl/images/0281/0300/1110a.png)
= 
= 133.368
= 3.124
= 3.124
= 3.124 
= 7.897 g
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Apure gold ring (c = 0.128 j/g°c) and pure silver ring (c = 0.235 j/g°c) have a total mass of 16.891...
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