Aclosed, rigid tank contains a two‐phase liquid–vapor mixture of refrigerant 22 initially at −20°c with a quality of 50.36%. energy transfer by heat into the tank occurs until the refrigerant is at a final pressure of 6 bar. determine the final temperature, in °c. if the final state is in the superheated vapor region, at what temperature, in °c, does the tank contain only saturated vapor?

Explanation:

The given data is as follows.

      Initial temperature of the system () =

So, at state 1 quality of the system is () = 0.5036

     Pressure at state 2, () = 6 bar

As, it is a rigid tank hence, the specific volumes at state 1 and state 2 are equal.

So,      

Now, from the saturated refrigerant-22 table taking specific volume at is as follows.

Thus,    

                       =

                       = 0.0007427 + 0.5036 (0.0926 - 0.0007427)

                       =

Hence,   =

Super heated refrigerant-22 tables take pressure at 6 bar. Interpolation method used to find the temperature is as follows.

                 and      

                  and

                    =

                    = 40 + 3.75

                    =

Saturated vapor refrigerant-22 takes specific volume at .

Therefore, interpolation method used to find the temperature will be as follows.

                   and    

                   and        

                               =

                          = -1.45 + 1.50

                          =

Thus, we can conclude that at tank contains only saturated vapor.

i wish i could but this one is weird give me abc and i can solve it.

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.