2n2h4(l) + n2o4(l) → 3n2(g) + 4h2o(g) [balanced] how many moles of n2h4 is required to produce 28.3 g of n2? assume that all reactants react completely. molar mass of n2h4 = 32.06 g/mol molar mass of n2o4 = 92.02 g/mol molar mass of n2 = 28.02 g/mol molar mass of h2o = 18.02 g/mol group of answer choices

0.67 moles of

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.

To calculate the moles, we use the equation:

According to stoichiometry:

3 moles of is produced by 2 moles of

Thus 1 mole of is produced by= of

Thus 0.67 moles of are required to produce 28.3 g of

answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.