Solid potassium chlorate decomposes into solid potassium chloride and oxygen gas. if 2.00 g potassium chlorate decomposes in a chamber with a fixed volume of 0.800 l, and temperature of 25.0◦c. what is the final chamber pressure? assume all the potassium chlorate decomposes. express your answer in atmospheres.

Answer : The final chamber pressure is 0.746 atm.

Explanation:

First we have to calculate the moles of .

Molar mass of = 122.5 g/mole

Now we have to calculate the moles of .

The balanced chemical reaction will be:

From the balanced reaction we conclude that,

As, 2 moles of react to give 3 moles of

So, 0.0163 moles of react to give moles of

Now we have to calculate the pressure of gas.

Using ideal gas equation:

where,

P = pressure of gas = ?

V = volume of gas = 0.800 L

T = temperature of gas =

R = gas constant = 0.0821 L.atm/mole.K

n = number of moles of gas = 0.0244 mole

Now put all the given values in the ideal gas equation, we get:

Therefore, the final chamber pressure is 0.746 atm.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

they are both synthetic elements

explanation:

d