What is the de broglie wavelength of an electron traveling at 1.62×105 m/s ?

0.449  10^(-8)  meters

meters

Explanation:

Use the deBroglie equation for the wavelength (lambda):

where h stands for the Plank constant:

m stands for the mass of the electron:

and v is the given velocity:

Evaluating lambda for these values:

answer

the ions in solute supperate from eachouthere

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.