What is the equilibrium partial pressure of water vapor above a mixture of 62.9 g h2o and 33.2 g hoch2ch2oh at 55 °c. the partial pressure of pure water at 55.0 °c is 118.0 mm hg. assume ideal behavior for the solution.

Answer : The partial pressure of is 102.3 mmHg.

Explanation :

As per question,

Mass of = 62.9 g

Mass of = 33.2 g

Molar mass of = 18 g/mole

Molar mass of = 62 g/mole

First we have to calculate the moles of and .

Now we have to calculate the mole fraction of and .

Now we have to partial pressure of .

According to the Raoult's law,

where,

= partial pressure of water vapor

= total pressure of gas

= mole fraction of water vapor

Therefore, the partial pressure of is 102.3 mmHg.

listen, you cant how young you were.

"you didn't chose the stud life. the stud life chose you."

the correct answer to this question is 2