To determine whether a shiny gold-colored rock is actually gold, a chemistry student decides to measure its heat capacity. she first weighs the rock and finds that it has a mass of 4.7 g. she then finds that, upon absorption of 52.7 j of heat, the rock undergoes a rise in temperature from 25 ∘c to 57 ∘c. find the specific heat capacity of the substance comprising the rock.

The answer to your question is: Cp = 350.4 J/ kg°C

Explanation:

Data

mass = m = 4.7 g   convert grams to kilograms  0.0047 kg

heat= Q = 52.7 J

Temperature = 25 - 57 °C

Formula

Q = mCpΔT    solve for Cp

Cp = Q / mΔT

Process

Cp = 52.7 / [(0.0047)(57 - 25)]            Substitution

Cp = 52.7 / 0.1504                                

Cp = 350.4 J/ kg°C

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.