Aroom contains four single-pane windows of size 5 ft by 2.5 ft. the thickness of the glass is 1/4 in. if the inside glass surface is at 60°f and the outside surface is at 30°f, estimate the heat loss through the windows 0ht

Explanation:

The given data is as follows.

           Area = = 12.5

             L = 0.25 in = 0.0208 ft     (as 1 inch = 0.0833 ft)

      ,        

               k (thermal conductivity) = 0.8

Formula to calculate the heat loss will be as follows.

               Q =

Putting the given values into the above formula as follows.

             Q =

                 =

                 = 14285.7 Btu/hr

So,

                  =

                  = 57142.8 Btu/hr

Thus, we can conclude that heat loss through the windows is 57142.8 Btu/hr.

answer; /// i do believe that the correct answer is (c)nuclear bond

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole