Two hundred kg of liquid contains 30% butane, 40% pentane, and the rest hexane (mass %) determine: the mole fraction composition of the liquid the mass fraction composition on hexane free basis 1. 2.

The mole fraction composition of the liquid is :

Mole fraction of butane, pentane and hexane are 0.3638,0.3908 and 0.2454 respectively.

Explanation:

Mass of the liquid mixture = 200 g

Percentage of butane = 30%

Mass of butane =

Moles of butane =

Percentage of pentane= 40%

Mass of pentane=

Moles of pentane=

Percentage of hexane = 100% - 30% - 40% = 30%

Mass of hexane =

Moles of hexane =

Mole fraction of butane, pentane and hexane :

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explanation:

elements make up everything, and they combine to make compounds.

the answer is c