Chemistry, 25.09.2019 02:00 agreisha

Pure nitrogen (n2) and pure hydrogen (h2) are fed to a mixer. the product stream has 40.0% mole nitrogen and the balance hydrogen. the product flow rate is 1,368 kg/hr. calculate the feed rate of pure nitrogen to the mixer in kg/hr.

Answers: 2

Show answers

Answers

Answer from: hannah5143

Explanation:

The given data is as follows.

Mass flow rate of mixture = 1368 kg/hr

$N_{2}$ in feed = 40 mole%

This means that $H_{2}$ in feed = (100 - 40)% = 60%

We assume that there are 100 total moles/hr of gas $(N_{2} + H_{2})$ in feed stream.

Hence, calculate the total mass flow rate as follows.

40 moles/hr of N_{2}/hr (28 g/mol of $N_{2}$ ) + 60 moles/hr of $H_{2}/hr$ (2 g/mol of $H_{2}$ )

$40 \times 28 g/hr + 60 \times 2 g/hr$

= 1120 g/hr + 120 g/hr

= 1240 g/hr

= $\frac{1240}{1000}$ (as 1 kg = 1000 g)

= 1.240 kg/hr

Now, we will calculate mol/hr in the actual feed stream as follows.

$\frac{100 mol/hr}{1.240 kg/hr} \times 1368 kg/hr$

= 110322.58 moles/hr

It is given that amount of nitrogen present in the feed stream is 40%. Hence, calculate the flow of $N_{2}$ into the reactor as follows.

$0.4 \times 110322.58 moles/hr$

= 44129.03 mol/hr

As 1 mole of nitrogen has 28 g/mol of mass or 0.028 kg.

Therefore, calculate the rate flow of $N_{2}$ into the reactor as follows.

$0.028 kg \times 44129.03 mol/hr$

= 1235.612 kg/hr

Thus, we can conclude that the the feed rate of pure nitrogen to the mixer is 1235.612 kg/hr.

Answer from: Quest

$\frac{239}{94}pu+\frac{1}{0}n ====> \frac{y}{z}x+\frac{134}{54}xe+3\frac{1}{0}$

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137 subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54 subtract 54 from both sides.

40 = z

answer

$\frac{103}{40}x=\frac{103}{40}zr$

Answer from: Quest

your answer is a. the enthalpy of formation for a pure element in its standard state is always positive.

Another question on Chemistry

Chemistry, 21.06.2019 19:00

0.66y = 0.9x + 0.48 if y has a value of 108.45 what is the value of x?

Answers: 1

Answer

Chemistry, 21.06.2019 22:30

Asolution contains 225 g of sodium chloride, nacl, dissolved in enough water to make a 0.25 l of solution. what is the molarity of the solution? a. 3.88 m, b. 1.03 m, c. 1.5 m, d. 15.5 m

Answers: 3

Answer

Chemistry, 22.06.2019 12:30

Acontrol during an experiment. might change remains constant does not exist does change

Answers: 1

Answer

Chemistry, 22.06.2019 22:30

[ou.03jthe pictures below show the wavelengths and intensities of electromagnetic radiations emitted by three stars, star 1, star 2, and star 3. intensity intensity- intensity- 1000 3500 6000 8500 11000 wavelength (a) star 1 1000 3500 6000 8500 11000 1000 3500 6000 8500 11000 wavelength (a) wavelength (a) star 2 star 3 which of these statements is correct about the color of the three stars? star 2 is white in color o star 2 is yellow in color star 1 and star 3 are yellow in color star 1 and star 3 are white in color

Answers: 1

Answer

You know the right answer?

Pure nitrogen (n2) and pure hydrogen (h2) are fed to a mixer. the product stream has 40.0% mole nitr...

Questions