When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water according to the reaction below. how many grams of hydrogen were required to form 3.00 moles of water?

The answer to your question is: 6 grams of hydrogen

Explanation:

Data

3.0 moles of hydrogen

1.5 moles of oxygen

3 moles of water

# of grams of hydrogen required to form 3 moles of water?

Equation

                  H₂    +   1/2 O₂        ⇒        H₂O

                3 mole    1.5 moles           3 moles

 Atomic weight of H₂ = 2 g

                         1 mole   2 g

                         3 moles    x

                          x = 3(2)/1 = 6 grams of hydrogens

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.