Chemistry, 24.09.2019 22:00 emilypzamora11

The rate law for the reaction 2a + b →c is –ra= kaca2cbwithka= 25 (l/mol)2sec. what arekbandkc?

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Answer from: jchse4365

Explanation:

The given reaction equation is as follows.

$2A + B \rightarrow C$

So, rate constants for different reactants and products written as follows.

$\frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}$

As per the reaction equation, the stoichiometric coefficients of reactants and products are as follows.

A = -2

B = -1

C = 1

Therefore,

$\frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}$

$\frac{-k_{A}}{-2} = \frac{-k_{B}}{-1} = \frac{k_{C}}{1}$

$\frac{-k_{A}}{-2} = k_{B} = k_{C}$

Hence, $k_{B} = k_{C}$ = $\frac{25}{2} (L/mol)^{2}$

= 12.5 $(L/mol)^{2}$

Thus, we can conclude that $k_{B}$ and $k_{C}$ are 12.5 $(L/mol)^{2}$ .

Answer from: Quest

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Answer from: Quest

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explanation:

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