Hemoglobin is a large protein molecule that is responsible for carrying oxygen through the blood. iron ions are a relatively small component of hemoglobin. there are four fe2+ions that are part of the much larger hemoglobin structure. in a single red blood cell there are 2.50x108molecules of hemoglobin. if a single fe2+ion has an atomic radius of 75.1 pm and a redblood cell has a volume of 95 μm3, what percentage of the total red blood cell volume is taken up by fe2+ions?

The percentage of volume taken by iron(II) in the blood cell is 0.0019%.

Explanation:

Radius of iron(II) ions ,r= 75.1 pm =

1 pm = 10^{-6} μm

Volume of sphere  =

Volume of single iron(II) ion = V

Number of iron(II) ions in one hemoglobin structure = 4

Number of hemoglobin structure in blood cell = molecules

Then number of iron (II) ions in molecules of hemoglobin:

Volume of ions of iron =

Volume of the  hemoglobin structure,V' =

Percentage volume of iron (II) ions in a single blood cell:

=

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.