if 20.15 ml of 0.150 m ammonium hydroxide is required to neutralize 13.5 ml of sulfurous acid, what is the molarity of the acid?
h2so3(aq)+2nh4oh(aq)→(nh4)2so3(aq)+ 2h2o(l)

The molarity of the acid is 0.112 M

Explanation:

In the reaction of neutralization, 2 moles of NH₄OH react with 1 mol H₂SO₃. Then, in the equivalence point, the number of moles of NH₄OH will be twice the number of moles of H₂SO₃.

In the equivalence point:

moles H₂SO₃ = 1/2 * moles NH₄OH

Then, let´s calculate the number of moles of NH₄OH consumed in the reaction:

number of moles = molar concentration * volume (l)

number of moles NH₄OH = 0.150 mol/l * 0.02015 l = 3.02 x 10⁻³ mol  

Then, the number of moles of H₂SO₃ will be:

moles H₂SO₃ = 1/2 * moles NH₄OH

moles H₂SO₃ = 1/2 * 3.02 x 10⁻³ mol  

moles H₂SO₃ = 1.51 x 10⁻³ moles

Since this number of moles was initially in 13. 5 ml, the concentration of H₂SO₃  will be:

molar concentration = number of moles / volume (l)

molar concentration =  1.51 x 10⁻³ moles / 0.0135 l = 0.112 M  

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cytokinesis is the splitting of a cell membrane to form 2 identical daughter cells. it's similar to mitosis as both cells have identical copies of dna and cytokinesis is a step in the mitotic cycle.

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >