The equation for the combustion of ethanol is: c2hsoh(i)+302(g) 2c02(g) +3h20(i) given (in kj mol2): = +347 e(c-c) e(c-h) e(c-o e(0=0) e(c o) e(o-h) = +410 = +336 +496 +805 +465 calculate the enthalpy change of the above reaction. (a) the standard enthalpy change of combustion of ethanol is-1367.3 kj mol1. (b) suggest why this value differs from the value obtained using bond energies.
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The equation for the combustion of ethanol is: c2hsoh(i)+302(g) 2c02(g) +3h20(i) given (in kj mol2)...
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