When 50.08 g of 1.00 m naoh at 23 c is added to 50.22 g of 1.00 m hcl at 23 c, the resulting temperature of the mixture is 29.7 c. (assume that the calorimeter constant is equal to zero. assume that the solutions have the same specific heat capacity (4.184 j/g·k) and density (1.00 g/ml) as water. take care with signs.) a) what is δt for this process? b) calculate qsolution (in j) for this process. c) calculate qreaction (in j) for this process. page 2 of 2 d) calculate the moles of naoh and the moles of hcl used in the reaction. determine whether naoh or hcl is the limiting reactant. e) what is the enthalpy change (δhrxn, in kj/mol) for this process per mol of the limiting reactant? f) is the reaction of naoh with hcl an endothermic or exothermic process?

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

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ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.