Answer : 182 gexplanation :
the complete reaction for the formation of aluminum oxide is as follows;
4al + 3
> 2![al_{2}o_{3}](/tex.php?f=al_{2}o_{3})
so if the molar mass of the
is 32.0 g/mol and
so, to form 3.80 mol of
(3.80 mol
) x (3 mol
) x (32.0 g
)
dividing by 2 because two moles of
will be formed;
∴ 364.8/2 = 182.4g ![o_{2}](/tex.php?f= o_{2})