It is possible to predict the equilibrium constant of a reaction by combining two or more reactions for which the value of k is known. when combining equilibrium constants, it is important to note the following: when a reaction is reversed, its k value is inverted; that is, kreverse=1/kforward. when the coefficients of a reaction are multiplied by a factor, the k value is raised to the power of that factor. when reactions are added, their k values are multiplied. part a determine the value of the equilibrium constant, kgoal, for the reaction c(s)+12o2(g)+h2(g)⇌12ch3oh(g)+12co( g), kgoal=? by making use of the following information: 1. co2(g)+3h2(g)⇌ch3oh(g)+h2o(g), k1 = 1.40×102 2. co(g)+h2o(g)⇌co2(g)+h2(g), k2 = 1.00×105 3. 2c(s)+o2(g)⇌2co(g), k3 = 2.10×1047 express your answer numerically. view available hint(s) kgoal = nothing part b determine the equilibrium constant, kgoal, for the reaction 4pcl5(g)⇌p4(s)+10cl2(g), kgoal=? by making use of the following information: p4(s)+6cl2(g)⇌4pcl3(g), k1=2.00×1019 pcl5(g)⇌pcl3(g)+cl2(g), k2=1.13×10−2 express your answer numerically.

  remember that hf is only the energy of one photon. not two. not three. one.  1) 5.12 * 10^3 photons  find the energy of one photon, then determine how many photons are needed to reach the sensitivity.  e = hf  = (6.626 * 10^-34 js)(5.95 * 10^19 hz)  = 3.94247 * 10^-14 j per photon  (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons  round to three sig figs.  2) 5.77 * 10^-17 j  energy of pulse = energy per photon * number of photons  = hfn  = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250)  = 5.774559 * 10^-17 j  round to three sig figs.  3) 4.07 * 10^8 kj/mol  10^12 pm = 1 m  c = fλ  f = c/λ  e = hf  = hc/λ  = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol)  = 40702571.4 kj/mol  round to three sig figs.  4) 9.94 * 10^-1 m  e = hc/λ  λ = hc / e  = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j)  = 0.9939 m  round to three sig figs.  5) 9.06 * 10^3 photons  energy of pulse = energy per photon * number of photons  number of photons = energy of pulse / energy per photon  = energy of pulse / (hf)  = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)]  = 9055.23695 photons  round to three sig figs.  6) 2.78 * 10^-15 j  this is problem 1, except in reverse.  sensitivity = minumum number of photons * energy per photon  = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz)  = 2.78070758 × 10^-15 j  round to three sig figs.