Which of the following is true about oxygen (o), sulfur (s) and neon (ne)? (choose 3)
a. oxygen and neon are in the same group and have the same number of valence electrons.
b. oxygen and sulfur are in the same period and have the same number of electron shells.
c. oxygen and neon are in the same period and have the same number of electron shells.
d. oxygen and sulfur have the same number of valence electrons.
e. oxygen and sulfur are most similar because they are in the same family and have similar chemical properties.
f. oxygen and neon have similar chemical properties.

from the way I understand the question I think the answer is (B)

Explanation:

Because the distribution into shells of oxygen is 2,6 and in sulfur is 2,8,6 and oxygen has a 8th number of electrons and sulfur has the 16th number of electrons

Option C, option D and option E is correct

Explanation:

Atomic number of O = 8

Electronic configuration of O =

No. of valence electron = 6

Atomic number of S = 16

Electronic configuration of O =

No. of valence electron = 6

Atomic number of Ne = 10

Electronic configuration of Ne =

No. of valence electron = 8

No. of electron shell present in any atom is equal to principle quantum no.

So, no. of electron shell in O = 2

no. of electron shell in S = 3

no. of electron shell in Ne = 2

O is present in period 2 and group 16.

S is present in period 3 and group 16.

Ne is present in period 2 and group 16.

So, O and S are present in same group. Elements of same group or family display similar chemical properties.

So, among correct options are:

option C: Oxygen and Neon are in the same period and have the same number of electron shells.

Option D: Oxygen and Sulfur have the same number of valence electrons.

Option E: Oxygen and Sulfur are most similar because they are in the same family and have similar chemical properties.

a

explanation:

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence