Apiece of unknown metal with mass 68.6 g is heated to an initial temperature of 100 °c and dropped into 8.4 g of water
(with an initial temperature of 20 °c) in a calorimeter. the final temperature of the system is 52.1°c. the specific heat of
water is 4.184 j/g °c. what is the specific heat of the metal?

The metal has a specific heat of 0.34333 J / g °C

Explanation:

The amount of heat lost by the metal is equal to the amount heat won by the water

q(lost, metal) = q(gained, water)

Step 1: Given data

q = m*ΔT *Cp

⇒with m = mass of the substance

⇒with ΔT = change in temp = final temperature T2 - initial temperature T1

⇒with Cp = specific heat (Cpwater = 4.184J/g °C) (Cpmetam = TO BE DETERMINED)

mass of the metal = 68.6g

mass of the water = 8.4g

initial temperature metal = 100°C

final temperature metal = 52.1°C

initial temperature water = 20°C

final temperature water = 52.1 °C

Specific heat of water = 4.184 J/g °C

Step 2:

For this situation : we get for q = m*ΔT *Cp

q(lost, metal) = q(gained, water)

- mass of metal(ΔT)(Cpmetal) = mass of water (ΔT) (Cpwater)

-68.6 * (52.1 - 100) * Cpmetal = 8.4g * (52.1 - 20) * 4.184 J /g °C

-68.6 * (-47.9) * Cpmetal = 1128.17

Cpmetal = 1128.17 / (-68.6 *-47.9) = 0.34333 J / g °C

The metal has a specific heat of 0.34333 J / g °C

coral.

explanation:

coral. many marine organisms that produce calcium carbonate shells or skeletons are negatively impacted by increasing co2 levels and decreasing ph in seawater.

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.