You fill a rigid steel cylinder that has a volume of 20.0 l with nitrogen gas to a final pressure of 2.00 *10^4 kpa at 28c how many kilograms of n2 does the cylinder contain

Answer : The mass of gas is, 4477.8 g

Solution :

using ideal gas equation,

where,

n = number of moles of gas

w = mass of gas

P = pressure of the gas =

conversion :

T = temperature of the gas =

M = molar mass of gas = 28 g/mole

R = gas constant = 0.0821 Latm/moleK

V = volume of gas = 20 L

Now put all the given values in the above equation, we get the mass of gas.

Therefore, the mass of gas is, 4477.8 g

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2b2t

explanation:

2b2t