What is the specific heat (j/g c)of a metal who’s temp increases by 3.0 c when 17.5 g of metal was heated with 38.5 j

0.733 J/g °C

Explanation:

Step 1 : Write formule of specific heat

Q = mc Δ T

with Q = heat transfer (J)

with m = mass of the substance

with c = specific heat ⇒ depends on material and phase ( J/g °C)

Δ T = Change in temperature

in this case :

Q = 38.5 J

m = 17.5g

c= has to be determined

Δ T = 3 (°C)

Step 2:  Calculating specific heat

⇒ via the formule Q = mc Δ T

38.5 J = 17.5g * c * 3

38.5 = 52.5 *c

c = 38.5 / 52.5

c = 0.733 J/g °C ⇒ 0.733 is reported to three significant digits due to the precision.

The specific heat of this metal is 0.733 J/g °C

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o