Hexane is a common laboratory solvent and a component of petrol. its combustion reaction is as follows: 2 c6h14 (9) + 19 02(9) +12 co2(g) + 14 h20(1) arh=-8326 kj mol-1 use the reaction enthalpy value to calculate the heat in (kj) released by combustion of 0.121 mol of hexane. (give your answer as a positive number to at least three significant figures and do not include the units in the answer box)

Answer : The heat released by the combustion of 1.121 mol of hexane (kJ) is,

Explanation :

The given balanced reaction is,

Given:

Moles of hexane = 0.121 mol

= -8326 kJ/mol

The negative sign indicate that the reaction exothermic or amount of heat released.

As, 1 mole of hexane released heat = 8326 kJ

So, 0.121 mole of hexane released heat = 8326 × 0.121 = 1007.446 ≈

Therefore, the heat released by the combustion of 1.121 mol of hexane is .

h let me think